Dictionary of cubes

Write a Python program to create {k: k³} for k from 1 to n.

n = 4

{1: 1, 2: 8, 3: 27, 4: 64}

Approach

1. A dict comprehension over range(1, n + 1).

Solution

n = 4print({k: k ** 3 for k in range(1, n + 1)})

{1: 1, 2: 8, 3: 27, 4: 64}

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