Square every dictionary value

Write a Python function that returns a new dictionary with every value squared.

{"a": 4, "b": 3, "c": 12, "d": 6}

{'a': 16, 'b': 9, 'c': 144, 'd': 36}

Approach

1. Dict comprehension.

Solution

def square_values(d):    return {k: v * v for k, v in d.items()} print(square_values({"a": 4, "b": 3, "c": 12, "d": 6}))

{'a': 16, 'b': 9, 'c': 144, 'd': 36}

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