Python Practice Problems

Python practice problems help beginners to become experts in a python programming language with a small amount of practice effort.

Squares of even, cubes of odd

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Python Practice › Dictionary Programs › Program 7

Squares of even, cubes of odd

EasyDictionary Programs · 7 of 94

Write a Python program that stores squares of even numbers and cubes of odd numbers in a dictionary using a comprehension.

Input
[4, 5, 6, 2, 1, 7, 11]
Output
{4: 16, 5: 125, 6: 36, 2: 4, 1: 1, 7: 343, 11: 1331}

Approach

  1. A conditional expression picks the power.

Solution

Python
numbers = [4, 5, 6, 2, 1, 7, 11]print({n: n ** 2 if n % 2 == 0 else n ** 3 for n in numbers})
Output
{4: 16, 5: 125, 6: 36, 2: 4, 1: 1, 7: 343, 11: 1331}

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More dictionary programs

#8EasyClear a dictionary#9EasyRemove duplicate values#10EasyCharacter counts of a string#11EasySort a dictionary by key

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Dictionary from two lists

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Python Practice › Dictionary Programs › Program 6

Dictionary from two lists

EasyDictionary Programs · 6 of 94

Write a Python program to create a dictionary from a list of keys and a list of values.

Input
["a", "b", "c", "d", "e"], [12, 23, 24, 25, 15, 16]
Output
{'a': 12, 'b': 23, 'c': 24, 'd': 25, 'e': 15}

Approach

  1. dict(zip(keys, values)); zip stops at the shorter list.

Solution

Python
keys = ["a", "b", "c", "d", "e"]values = [12, 23, 24, 25, 15, 16]print(dict(zip(keys, values)))
Output
{'a': 12, 'b': 23, 'c': 24, 'd': 25, 'e': 15}

Line by line

Line 3

The extra value 16 is ignored because zip stops when the shorter list ends.

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More dictionary programs

#7EasySquares of even, cubes of odd#8EasyClear a dictionary#9EasyRemove duplicate values#10EasyCharacter counts of a string

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Odd and even keys

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Python Practice › Dictionary Programs › Program 5

Odd and even keys

EasyDictionary Programs · 5 of 94

Write a Python program to get lists of the items with even keys and with odd keys.

Input
{1: 25, 5: "abc", 8: "pqr", 21: "xyz", 12: "def", 2: "utv"}
Output
Even Key = [[8, 'pqr'], [12, 'def'], [2, 'utv']]
Odd Key = [[1, 25], [5, 'abc'], [21, 'xyz']]

Approach

  1. Filter items() by key % 2.

Solution

Python
d = {1: 25, 5: "abc", 8: "pqr", 21: "xyz", 12: "def", 2: "utv"}even = [[k, v] for k, v in d.items() if k % 2 == 0]odd = [[k, v] for k, v in d.items() if k % 2 == 1]print("Even Key =", even)print("Odd Key =", odd)
Output
Even Key = [[8, 'pqr'], [12, 'def'], [2, 'utv']]
Odd Key = [[1, 25], [5, 'abc'], [21, 'xyz']]

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More dictionary programs

#6EasyDictionary from two lists#7EasySquares of even, cubes of odd#8EasyClear a dictionary#9EasyRemove duplicate values

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Concatenate two dictionaries

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Python Practice › Dictionary Programs › Program 4

Concatenate two dictionaries

EasyDictionary Programs · 4 of 94

Write a Python program to concatenate two dictionaries.

Input
{"Name": "Harry", "Rollno": 345, "Address": "Jordan"}, {"Age": 25, "salary": "$25k"}
Output
{'Name': 'Harry', 'Rollno': 345, 'Address': 'Jordan', 'Age': 25, 'salary': '$25k'}
{'Name': 'Harry', 'Rollno': 345, 'Address': 'Jordan', 'Age': 25, 'salary': '$25k'}

Approach

  1. | (Python 3.9+) creates a merged dict; update changes one in place.

Solution

Python
dict1 = {"Name": "Harry", "Rollno": 345, "Address": "Jordan"}dict2 = {"Age": 25, "salary": "$25k"}print(dict1 | dict2)dict1.update(dict2)print(dict1)
Output
{'Name': 'Harry', 'Rollno': 345, 'Address': 'Jordan', 'Age': 25, 'salary': '$25k'}
{'Name': 'Harry', 'Rollno': 345, 'Address': 'Jordan', 'Age': 25, 'salary': '$25k'}

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More dictionary programs

#5EasyOdd and even keys#6EasyDictionary from two lists#7EasySquares of even, cubes of odd#8EasyClear a dictionary

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Move items to another dictionary

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Python Practice › Dictionary Programs › Program 3

Move items to another dictionary

EasyDictionary Programs · 3 of 94

Write a Python program to move all items from dict1 to dict2, leaving dict1 empty.

Input
{"name": "john", "city": "London", "country": "UK"}
Output
dict1 = {}
dict2 = {'name': 'john', 'city': 'London', 'country': 'UK'}

Approach

  1. update dict2, then clear dict1.

Solution

Python
dict1 = {"name": "john", "city": "London", "country": "UK"}dict2 = {}dict2.update(dict1)dict1.clear()print("dict1 =", dict1)print("dict2 =", dict2)
Output
dict1 = {}
dict2 = {'name': 'john', 'city': 'London', 'country': 'UK'}

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More dictionary programs

#4EasyConcatenate two dictionaries#5EasyOdd and even keys#6EasyDictionary from two lists#7EasySquares of even, cubes of odd

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Square of every value

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Python Practice › Dictionary Programs › Program 2

Square of every value

EasyDictionary Programs · 2 of 94

Write a Python program to print the square of every value in a dictionary.

Input
{"a": 5, "b": 3, "c": 6, "d": 8}
Output
a : 25
b : 9
c : 36
d : 64

Approach

  1. Loop over items().

Solution

Python
d = {"a": 5, "b": 3, "c": 6, "d": 8}for key, value in d.items():    print(key, ":", value ** 2)
Output
a : 25
b : 9
c : 36
d : 64

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More dictionary programs

#3EasyMove items to another dictionary#4EasyConcatenate two dictionaries#5EasyOdd and even keys#6EasyDictionary from two lists

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Add elements to a dictionary

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Python Practice › Dictionary Programs › Program 1

Add elements to a dictionary

EasyDictionary Programs · 1 of 94

Write a Python program to add elements to a dictionary.

Input
{"name": "Asha"}
Output
{'name': 'Asha', 'city': 'Pune', 'age': 29, 'role': 'tester'}

Approach

  1. Assign to a new key, or use update() for several keys.

Solution

Python
person = {"name": "Asha"}person["city"] = "Pune"person.update({"age": 29, "role": "tester"})print(person)
Output
{'name': 'Asha', 'city': 'Pune', 'age': 29, 'role': 'tester'}

Line by line

Line 2

Assigning to a key that does not exist adds it.

Line 3

update adds (or replaces) several keys at once.

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More dictionary programs

#2EasySquare of every value#3EasyMove items to another dictionary#4EasyConcatenate two dictionaries#5EasyOdd and even keys

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Python String Programs with Solutions

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Python Practice › String Programs

Python String Programs with Solutions

106 programs101 easy5 medium0 hard

106 string programs that cover slicing, searching, counting, replacing, splitting and joining text. They are among the most common Python interview questions, and each one has an explained solution with real output.

Before you start

Read the Strings & Methods and String Formatting & f-strings lesson first if the topic is new to you.

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Arithmetic operations on two numbers

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Python Practice › Basic Programs › Program 40

Arithmetic operations on two numbers

EasyBasic Programs · 40 of 40

Write a Python program to perform all the basic arithmetic operations on two numbers.

Input
a = 17, b = 5
Output
Addition        22
Subtraction     12
Multiplication  85
Division        3.4
Floor division  3
Remainder       2
Power           1419857

Approach

  1. Apply each arithmetic operator and print the results in a table.

Solution

Python
a, b = 17, 5operations = {    "Addition": a + b,    "Subtraction": a - b,    "Multiplication": a * b,    "Division": a / b,    "Floor division": a // b,    "Remainder": a % b,    "Power": a ** b,}for name, value in operations.items():    print(f"{name:<15} {value}")
Output
Addition        22
Subtraction     12
Multiplication  85
Division        3.4
Floor division  3
Remainder       2
Power           1419857

Line by line

Lines 2-10

A dictionary maps each operation’s name to its result.

Lines 11-12

The loop prints each pair; :<15 pads the name to 15 characters so the values line up.

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More basic programs

#36EasyHCF (GCD) of two numbers#37EasyLCM of two numbers#38EasySquare root of a number#39EasyVolume of a sphere

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Volume of a sphere

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Python Practice › Basic Programs › Program 39

Volume of a sphere

EasyBasic Programs · 39 of 40

Write a Python program to calculate the volume of a sphere. Volume = 4/3 × π × r³.

Input
r = 6
Output
Volume: 904.78

Approach

  1. Apply the formula with math.pi.

Solution

Python
import math r = 6volume = 4 / 3 * math.pi * r ** 3print("Volume:", round(volume, 2))
Output
Volume: 904.78

Line by line

Line 4

The radius is cubed (r ** 3).

Note

The original exercise wrote the formula as 4/3 × π × r² with π = 3. The correct formula uses r³, and math.pi gives an accurate π.

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More basic programs

#40EasyArithmetic operations on two numbers

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