Python Practice Problems

Python practice problems help beginners to become experts in a python programming language with a small amount of practice effort.

Surface area of a cylinder

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Python Practice › Basic Programs › Program 18

Surface area of a cylinder

EasyBasic Programs · 18 of 40

Write a Python program to calculate the surface area of a cylinder. Area = 2πrh + 2πr².

Input
r = 3, h = 10
Output
Surface area: 245.04

Approach

  1. Curved surface = 2πrh; the two circular ends = 2πr².
  2. Add them.

Solution

Python
import math r = 3h = 10curved = 2 * math.pi * r * hends = 2 * math.pi * r ** 2print("Surface area:", round(curved + ends, 2))
Output
Surface area: 245.04

Line by line

Lines 5-6

Splitting the formula into named parts makes each step easy to check.

Line 7

The total is rounded to two decimals.

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Surface area of a cube

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Python Practice › Basic Programs › Program 17

Surface area of a cube

EasyBasic Programs · 17 of 40

Write a Python program to calculate the surface area of a cube. Surface area = 6 × a².

Input
a = 4
Output
Surface area of the cube: 96

Approach

  1. A cube has 6 square faces, each of area a².

Solution

Python
a = 4surface_area = 6 * a ** 2print("Surface area of the cube:", surface_area)
Output
Surface area of the cube: 96

Line by line

Line 2

Six faces times the area of one face, a ** 2.

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#18EasySurface area of a cylinder#19MediumCheck an Armstrong number#20EasySimple interest#21EasyPrint the current date in a format

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Area of a circle

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Python Practice › Basic Programs › Program 16

Area of a circle

EasyBasic Programs · 16 of 40

Write a Python program to calculate the area of a circle. Area = π × r².

Input
r = 7
Output
Area: 153.94

Approach

  1. Use math.pi for an accurate value of π.
  2. Multiply π by the radius squared.

Solution

Python
import math r = 7area = math.pi * r ** 2print("Area:", round(area, 2))
Output
Area: 153.94

Line by line

Line 4

math.pi is π to 15 decimal places, more accurate than 3.14.

Line 5

round(area, 2) keeps two decimals for display.

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More basic programs

#17EasySurface area of a cube#18EasySurface area of a cylinder#19MediumCheck an Armstrong number#20EasySimple interest

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Area of a square

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Python Practice › Basic Programs › Program 15

Area of a square

EasyBasic Programs · 15 of 40

Write a Python program to calculate the area of a square. Area = side × side.

Input
side = 6.5
Output
Area of the square: 42.25

Approach

  1. Multiply the side by itself.

Solution

Python
side = 6.5area = side * sideprint("Area of the square:", area)
Output
Area of the square: 42.25

Line by line

Line 2

side * side (or side ** 2) is the area.

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#16EasyArea of a circle#17EasySurface area of a cube#18EasySurface area of a cylinder#19MediumCheck an Armstrong number

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Formula (a – b)³ = a³ – 3a²b + 3ab² – b³

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Python Practice › Basic Programs › Program 14

Formula (a – b)³ = a³ – 3a²b + 3ab² – b³

MediumBasic Programs · 14 of 40

Write a Python program to solve the formula (a – b)³ = a³ – 3a²b + 3ab² – b³.

Input
a = 7, b = 2
Output
125 125 True

Approach

  1. Calculate both sides and compare them.

Solution

Python
a = 7b = 2 left = (a - b) ** 3right = a ** 3 - 3 * a ** 2 * b + 3 * a * b ** 2 - b ** 3print(left, right, left == right)
Output
125 125 True

Line by line

Line 5

3 * a 2 * b squares a first, because is evaluated before *.

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#15EasyArea of a square#16EasyArea of a circle#17EasySurface area of a cube#18EasySurface area of a cylinder

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Formula (a + b)³ = a³ + 3ab(a + b) + b³

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Python Practice › Basic Programs › Program 13

Formula (a + b)³ = a³ + 3ab(a + b) + b³

MediumBasic Programs · 13 of 40

Write a Python program to solve the formula (a + b)³ = a³ + 3ab(a + b) + b³.

Input
a = 2, b = 3
Output
125 125 True

Approach

  1. Calculate both sides and compare them.

Solution

Python
a = 2b = 3 left = (a + b) ** 3right = a ** 3 + 3 * a * b * (a + b) + b ** 3print(left, right, left == right)
Output
125 125 True

Line by line

Line 5

3ab(a + b) in maths becomes 3 * a * b * (a + b) in Python; every multiplication needs an explicit *.

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#14MediumFormula (a – b)³ = a³ – 3a²b + 3ab² – b³#15EasyArea of a square#16EasyArea of a circle#17EasySurface area of a cube

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Formula a² – b² = (a – b)(a + b)

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Python Practice › Basic Programs › Program 12

Formula a² – b² = (a – b)(a + b)

EasyBasic Programs · 12 of 40

Write a Python program to solve the formula a² – b² = (a – b)(a + b).

Input
a = 10, b = 6
Output
64 64 True

Approach

  1. Calculate both sides and compare them.

Solution

Python
a = 10b = 6 left = a ** 2 - b ** 2right = (a - b) * (a + b)print(left, right, left == right)
Output
64 64 True

Line by line

Lines 4-5

100 – 36 and 4 × 16 both give 64. Python does not multiply brackets automatically, so the * between them is required.

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#13MediumFormula (a + b)³ = a³ + 3ab(a + b) + b³#14MediumFormula (a – b)³ = a³ – 3a²b + 3ab² – b³#15EasyArea of a square#16EasyArea of a circle

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Formula (a – b)² = a² + b² – 2ab

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Python Practice › Basic Programs › Program 11

Formula (a – b)² = a² + b² – 2ab

EasyBasic Programs · 11 of 40

Write a Python program to solve the formula (a – b)² = a² + b² – 2ab.

Input
a = 9, b = 4
Output
25 25 True

Approach

  1. Calculate both sides and compare them.

Solution

Python
a = 9b = 4 left = (a - b) ** 2right = a ** 2 + b ** 2 - 2 * a * bprint(left, right, left == right)
Output
25 25 True

Line by line

Line 4

(a - b) 2 is 5 2.

Line 5

The expanded form gives the same value, 25.

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#12EasyFormula a² – b² = (a – b)(a + b)#13MediumFormula (a + b)³ = a³ + 3ab(a + b) + b³#14MediumFormula (a – b)³ = a³ – 3a²b + 3ab² – b³#15EasyArea of a square

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Formula (a + b)² = a² + b² + 2ab

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Python Practice › Basic Programs › Program 10

Formula (a + b)² = a² + b² + 2ab

EasyBasic Programs · 10 of 40

Write a Python program to solve the formula (a + b)² = a² + b² + 2ab and show both sides are equal.

Input
a = 4, b = 5
Output
(a + b)^2 = 81
a^2 + b^2 + 2ab = 81
Equal: True

Approach

  1. Calculate the left side and the right side separately.
  2. Print both and compare them.

Solution

Python
a = 4b = 5 left = (a + b) ** 2right = a ** 2 + b ** 2 + 2 * a * bprint("(a + b)^2 =", left)print("a^2 + b^2 + 2ab =", right)print("Equal:", left == right)
Output
(a + b)^2 = 81
a^2 + b^2 + 2ab = 81
Equal: True

Line by line

Line 4

The brackets make Python add before squaring.

Line 5

binds tighter than and +, so a 2 + b * 2 + 2 * a * b follows normal maths order.

Line 8

== returns True, confirming the identity for these values.

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More basic programs

#11EasyFormula (a – b)² = a² + b² – 2ab#12EasyFormula a² – b² = (a – b)(a + b)#13MediumFormula (a + b)³ = a³ + 3ab(a + b) + b³#14MediumFormula (a – b)³ = a³ – 3a²b + 3ab² – b³

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Pythagoras theorem

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Python Practice › Basic Programs › Program 9

Pythagoras theorem

EasyBasic Programs · 9 of 40

Write a Python program to find the hypotenuse of a right-angled triangle using the Pythagoras theorem: a² + b² = c².

Input
a = 3, b = 4
Output
Hypotenuse c = 5.0
Check: True

Approach

  1. Compute a² + b².
  2. Take the square root to get c.

Solution

Python
import math a = 3b = 4c = math.sqrt(a ** 2 + b ** 2)print("Hypotenuse c =", c)print("Check:", a ** 2 + b ** 2 == c ** 2)
Output
Hypotenuse c = 5.0
Check: True

Line by line

Line 1

math provides sqrt().

Line 5

The hypotenuse is the square root of the sum of the squares of the other two sides.

Line 7

Squaring c again confirms the theorem holds.

Tip

math.hypot(a, b) computes the same value in one call.

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More basic programs

#10EasyFormula (a + b)² = a² + b² + 2ab#11EasyFormula (a – b)² = a² + b² – 2ab#12EasyFormula a² – b² = (a – b)(a + b)#13MediumFormula (a + b)³ = a³ + 3ab(a + b) + b³

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