Python Practice Problems

Python practice problems help beginners to become experts in a python programming language with a small amount of practice effort.

Positive or negative, even or odd

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Python Practice › If-Else Programs › Program 21

Positive or negative, even or odd

EasyIf-Else Programs · 21 of 64

Write a Python program to check whether a number is positive or negative and even or odd.

Input
26, -7, 0
Output
26 is positive and even
-7 is negative and odd
0 is zero and even

Approach

  1. Decide the sign with if-elif-else.
  2. Decide parity with a conditional expression.

Solution

Python
for n in [26, -7, 0]:    if n > 0:        sign = "positive"    elif n < 0:        sign = "negative"    else:        sign = "zero"    parity = "even" if n % 2 == 0 else "odd"    print(f"{n} is {sign} and {parity}")
Output
26 is positive and even
-7 is negative and odd
0 is zero and even

Line by line

Lines 2-7

Three branches cover positive, negative and zero.

Line 8

A one-line conditional expression picks “even” or “odd”.

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More if-else programs

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Check if a number is negative

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Python Practice › If-Else Programs › Program 20

Check if a number is negative

EasyIf-Else Programs · 20 of 64

Write a Python program to check whether a number is negative and print True or False.

Input
-45, 12
Output
-45 True
12 False

Approach

  1. Compare with 0 using <.

Solution

Python
for n in [-45, 12]:    is_negative = n < 0    print(n, is_negative)
Output
-45 True
12 False

Line by line

Line 2

A comparison already produces a boolean, so storing it directly is the simplest form of this if-else.

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#21EasyPositive or negative, even or odd#22EasyLarger of two numbers#23EasyCheck an uppercase character#24EasyCheck a lowercase character

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Check if a number is positive

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Python Practice › If-Else Programs › Program 19

Check if a number is positive

EasyIf-Else Programs · 19 of 64

Write a Python program to check whether a number is positive and print True or False.

Input
20, -5, 0
Output
20 True
-5 False
0 False

Approach

  1. A positive number is greater than 0; the comparison itself gives True or False.

Solution

Python
for n in [20, -5, 0]:    if n > 0:        print(n, True)    else:        print(n, False)
Output
20 True
-5 False
0 False

Line by line

Line 2

0 is neither positive nor negative, so it prints False.

Tip

print(n > 0) gives the same result without an if-else.

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#20EasyCheck if a number is negative#21EasyPositive or negative, even or odd#22EasyLarger of two numbers#23EasyCheck an uppercase character

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Pass or fail

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Python Practice › If-Else Programs › Program 18

Pass or fail

EasyIf-Else Programs · 18 of 64

Write a Python program that reads marks and prints Pass if they are greater than 35, otherwise Fail.

Input
45
Output
Enter marks: 45
Pass

Approach

  1. Read the marks with input() and convert to int.
  2. Compare with 35.

Solution

Python
marks = int(input("Enter marks: "))if marks > 35:    print("Pass")else:    print("Fail")
Outputtyped input: 45
Enter marks: 45
Pass

Line by line

Line 1

input() returns text; int() converts it.

Line 2

The task says greater than 35, so exactly 35 fails.

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More if-else programs

#19EasyCheck if a number is positive#20EasyCheck if a number is negative#21EasyPositive or negative, even or odd#22EasyLarger of two numbers

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Check a palindrome string

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Python Practice › If-Else Programs › Program 17

Check a palindrome string

EasyIf-Else Programs · 17 of 64

Write a Python program to check whether a string is a palindrome, ignoring case.

Input
"jaj", "Madam", "python"
Output
jaj is a palindrome
Madam is a palindrome
python is not a palindrome

Approach

  1. Lower-case the text and compare it with its reverse.

Solution

Python
for word in ["jaj", "Madam", "python"]:    text = word.lower()    if text == text[::-1]:        print(word, "is a palindrome")    else:        print(word, "is not a palindrome")
Output
jaj is a palindrome
Madam is a palindrome
python is not a palindrome

Line by line

Line 2

Lower-casing makes “Madam” read the same backwards.

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More if-else programs

#18EasyPass or fail#19EasyCheck if a number is positive#20EasyCheck if a number is negative#21EasyPositive or negative, even or odd

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Check a palindrome number

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Python Practice › If-Else Programs › Program 16

Check a palindrome number

EasyIf-Else Programs · 16 of 64

Write a Python program to check whether a number is a palindrome.

Input
121, 123
Output
121 is a palindrome
123 is not a palindrome

Approach

  1. Compare the number’s digits with their reverse.

Solution

Python
for n in [121, 123]:    if str(n) == str(n)[::-1]:        print(n, "is a palindrome")    else:        print(n, "is not a palindrome")
Output
121 is a palindrome
123 is not a palindrome

Line by line

Line 2

str(n)[::-1] reverses the digits as text.

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More if-else programs

#17EasyCheck a palindrome string#18EasyPass or fail#19EasyCheck if a number is positive#20EasyCheck if a number is negative

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Check voting eligibility

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Python Practice › If-Else Programs › Program 15

Check voting eligibility

EasyIf-Else Programs · 15 of 64

Write a Python program to check whether a person is eligible to vote (age 18 or above).

Input
17, 18, 45
Output
17 -> not eligible, wait 1 year(s)
18 -> eligible to vote
45 -> eligible to vote

Approach

  1. Compare the age with 18 using >=.

Solution

Python
for age in [17, 18, 45]:    if age >= 18:        print(age, "-> eligible to vote")    else:        print(age, "-> not eligible, wait", 18 - age, "year(s)")
Output
17 -> not eligible, wait 1 year(s)
18 -> eligible to vote
45 -> eligible to vote

Line by line

Line 2

>= includes exactly 18, which is the legal voting age in India.

Line 5

The else branch also tells how long to wait.

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More if-else programs

#16EasyCheck a palindrome number#17EasyCheck a palindrome string#18EasyPass or fail#19EasyCheck if a number is positive

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Largest of three numbers

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Python Practice › If-Else Programs › Program 14

Largest of three numbers

EasyIf-Else Programs · 14 of 64

Write a Python program to find the largest of three numbers.

Input
a = 45, b = 89, c = 23
Output
Largest: 89

Approach

  1. Compare each number with the other two using >=.

Solution 1: if-elif

Python
a, b, c = 45, 89, 23 if a >= b and a >= c:    largest = aelif b >= a and b >= c:    largest = belse:    largest = cprint("Largest:", largest)
Output
Largest: 89

Line by line

Line 3

a is the largest if it is at least as big as both others. >= handles equal values.

Lines 7-8

If neither a nor b is the largest, it must be c.

Solution 2: max()

Python
print(max(45, 89, 23))
Output
89

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More if-else programs

#15EasyCheck voting eligibility#16EasyCheck a palindrome number#17EasyCheck a palindrome string#18EasyPass or fail

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Check if a number is in a list

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Python Practice › If-Else Programs › Program 13

Check if a number is in a list

EasyIf-Else Programs · 13 of 64

Write a Python program to check whether a given number is present in a list of numbers.

Input
numbers = [12, 45, 7, 89, 33]; check 89 and 50
Output
89 found at index 3
50 is not in the list

Approach

  1. Use in; use index() to also report the position.

Solution

Python
numbers = [12, 45, 7, 89, 33] for n in [89, 50]:    if n in numbers:        print(n, "found at index", numbers.index(n))    else:        print(n, "is not in the list")
Output
89 found at index 3
50 is not in the list

Line by line

Line 5

index() is safe here because the if already confirmed the number is present.

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More if-else programs

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Interview process with nested if-else

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Python Practice › If-Else Programs › Program 12

Interview process with nested if-else

EasyIf-Else Programs · 12 of 64

Write a Python program that describes a two-round interview: a candidate who passes round 1 can take round 2, and passing both means placed. Use nested if-else.

Input
("passed", "passed"), ("passed", "failed"), ("failed", "-")
Output
--- round1=passed, round2=passed
Round 1 cleared
Round 2 cleared: you are placed
--- round1=passed, round2=failed
Round 1 cleared
Failed in round 2, please try next time
--- round1=failed, round2=-
Failed in round 1, please try next time

Approach

  1. The outer if checks round 1.
  2. Only inside it does an inner if check round 2.

Solution

Python
def interview(round1, round2):    if round1 == "passed":        print("Round 1 cleared")        if round2 == "passed":            print("Round 2 cleared: you are placed")        else:            print("Failed in round 2, please try next time")    else:        print("Failed in round 1, please try next time") for r1, r2 in [("passed", "passed"), ("passed", "failed"), ("failed", "-")]:    print(f"--- round1={r1}, round2={r2}")    interview(r1, r2)
Output
--- round1=passed, round2=passed
Round 1 cleared
Round 2 cleared: you are placed
--- round1=passed, round2=failed
Round 1 cleared
Failed in round 2, please try next time
--- round1=failed, round2=-
Failed in round 1, please try next time

Line by line

Line 2

The outer condition decides whether round 2 matters at all.

Lines 4-7

The inner if-else only runs for candidates who passed round 1.

Lines 8-9

A failed round 1 skips round 2 entirely.

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More if-else programs

#13EasyCheck if a number is in a list#14EasyLargest of three numbers#15EasyCheck voting eligibility#16EasyCheck a palindrome number

← All 64 If-Else Programs