Python If-else Problems

Python If-else Problems

Exam attendance eligibility

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Python Practice › If-Else Programs › Program 54

Exam attendance eligibility

EasyIf-Else Programs · 54 of 64

Write a Python program that allows a student into the exam only if attendance is at least 75%.

Input
attended 52 of 65 classes, 40 of 65 classes
Output
80.0% -> eligible
61.5% -> not eligible

Approach

  1. Calculate the percentage, then compare with 75.

Solution

Python
for attended in [52, 40]:    total = 65    percent = attended / total * 100    if percent >= 75:        print(f"{percent:.1f}% -> eligible")    else:        print(f"{percent:.1f}% -> not eligible")
Output
80.0% -> eligible
61.5% -> not eligible

Line by line

Line 3

Percentage = attended / total × 100.

Line 5

:.1f prints one decimal place.

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Absolute value

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Python Practice › If-Else Programs › Program 53

Absolute value

EasyIf-Else Programs · 53 of 64

Write a Python program to print the absolute value of a number.

Input
-1, 7
Output
-1 -> 1 | abs(): 1
7 -> 7 | abs(): 7

Approach

  1. If the number is negative, negate it; or use abs().

Solution

Python
for n in [-1, 7]:    if n < 0:        result = -n    else:        result = n    print(n, "->", result, "| abs():", abs(n))
Output
-1 -> 1 | abs(): 1
7 -> 7 | abs(): 7

Line by line

Lines 2-5

Negating a negative number makes it positive.

Line 6

The built-in abs() gives the same result.

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Discount on a bill

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Python Practice › If-Else Programs › Program 52

Discount on a bill

EasyIf-Else Programs · 52 of 64

A shop gives 20% off bills above 2000 and 10% off bills above 1000. Write a Python program to calculate the discount.

Input
1500, 2500, 800
Output
Bill 1500: discount 150.0, pay 1350.0
Bill 2500: discount 500.0, pay 2000.0
Bill 800: discount 0, pay 800

Approach

  1. Check the bigger threshold first.

Solution

Python
for bill in [1500, 2500, 800]:    if bill > 2000:        discount = bill * 0.20    elif bill > 1000:        discount = bill * 0.10    else:        discount = 0    print(f"Bill {bill}: discount {discount}, pay {bill - discount}")
Output
Bill 1500: discount 150.0, pay 1350.0
Bill 2500: discount 500.0, pay 2000.0
Bill 800: discount 0, pay 800

Line by line

Lines 2-5

Testing > 2000 first stops a 2500 bill from getting only 10%.

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Is the rectangle a square?

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Python Practice › If-Else Programs › Program 51

Is the rectangle a square?

EasyIf-Else Programs · 51 of 64

Write a Python program that takes the length and breadth of a rectangle and checks whether it is a square.

Input
length 4, breadth 5
Output
Length: 4
Breadth: 5
It is not a square

Approach

  1. A rectangle is a square when length equals breadth.

Solution

Python
length = float(input("Length: "))breadth = float(input("Breadth: "))if length == breadth:    print("It is a square")else:    print("It is not a square")
Outputtyped input: 4, 5
Length: 4
Breadth: 5
It is not a square

Line by line

Lines 1-2

float() accepts decimal lengths too.

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Bonus eligibility

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Python Practice › If-Else Programs › Program 50

Bonus eligibility

EasyIf-Else Programs · 50 of 64

Write a Python program that gives a 10% bonus to employees who have served more than 4 years.

Input
(5 years, salary 60000), (3 years, salary 45000)
Output
5 years: eligible, bonus = 6000.0
3 years: not eligible for a bonus

Approach

  1. Compare years with 4; calculate 10% of the salary when eligible.

Solution

Python
for years, salary in [(5, 60000), (3, 45000)]:    if years > 4:        bonus = salary * 10 / 100        print(f"{years} years: eligible, bonus = {bonus}")    else:        print(f"{years} years: not eligible for a bonus")
Output
5 years: eligible, bonus = 6000.0
3 years: not eligible for a bonus

Line by line

Line 3

10% of the salary.

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Which group of ten a number belongs to

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Python Practice › If-Else Programs › Program 49

Which group of ten a number belongs to

MediumIf-Else Programs · 49 of 64

Write a Python program that splits 1-100 into 10 groups (1-10, 11-20, … 91-100) and finds which group a number belongs to, using nested if-else.

Input
36, 100, 1, 105
Output
36 belongs to the 4th group
100 belongs to the 10th group
1 belongs to the 1st group
105 is outside 1-100

Approach

  1. Check the range is valid with the outer if.
  2. Calculate the group with (n - 1) // 10 + 1 inside it.

Solution

Python
def group_of(n):    if 1 <= n <= 100:        group = (n - 1) // 10 + 1        if group == 1:            suffix = "st"        elif group == 2:            suffix = "nd"        elif group == 3:            suffix = "rd"        else:            suffix = "th"        return f"{n} belongs to the {group}{suffix} group"    else:        return f"{n} is outside 1-100" for n in [36, 100, 1, 105]:    print(group_of(n))
Output
36 belongs to the 4th group
100 belongs to the 10th group
1 belongs to the 1st group
105 is outside 1-100

Line by line

Line 2

The outer check rejects values outside the range.

Line 3

Subtracting 1 makes 1-10 map to 0, 11-20 to 1 and so on; adding 1 gives the group number.

Lines 4-11

The inner if-else picks the English ordinal suffix.

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Roller coaster eligibility

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Python Practice › If-Else Programs › Program 48

Roller coaster eligibility

EasyIf-Else Programs · 48 of 64

Write a Python program to check whether a person can ride a roller coaster: eligible when age is greater than 12.

Input
15, 12
Output
15 -> You are eligible
12 -> You are not eligible

Approach

  1. Compare the age with 12 using >.

Solution

Python
for age in [15, 12]:    if age > 12:        print(age, "-> You are eligible")    else:        print(age, "-> You are not eligible")
Output
15 -> You are eligible
12 -> You are not eligible

Line by line

Line 2

“Greater than 12” excludes exactly 12.

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Check if a value is a dictionary

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Python Practice › If-Else Programs › Program 47

Check if a value is a dictionary

EasyIf-Else Programs · 47 of 64

Write a Python program to check whether a value is a dictionary.

Input
{"name": "Virat", "sport": "cricket"}
Output
It is a dictionary with keys ['name', 'sport']

Approach

  1. Use isinstance(value, dict).

Solution

Python
player = {"name": "Virat", "sport": "cricket"}if isinstance(player, dict):    print("It is a dictionary with keys", list(player))else:    print("It is not a dictionary")
Output
It is a dictionary with keys ['name', 'sport']

Line by line

Line 3

list(player) lists the dictionary’s keys.

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Check if a value is a list

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Python Practice › If-Else Programs › Program 46

Check if a value is a list

EasyIf-Else Programs · 46 of 64

Write a Python program to check whether a value is a list.

Input
[1, 3, 6, 8], (1, 3)
Output
[1, 3, 6, 8] True
(1, 3) False

Approach

  1. Use isinstance(value, list).

Solution

Python
for value in [[1, 3, 6, 8], (1, 3)]:    print(value, isinstance(value, list))
Output
[1, 3, 6, 8] True
(1, 3) False

Line by line

Line 2

A tuple is a different type, so it returns False.

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Check a boolean value

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Python Practice › If-Else Programs › Program 45

Check a boolean value

EasyIf-Else Programs · 45 of 64

Write a Python program to check whether a value is of boolean type.

Input
True, 1
Output
True is a boolean
1 is not a boolean

Approach

  1. Use isinstance(value, bool); note 1 is an int, not a bool.

Solution

Python
for value in [True, 1]:    if isinstance(value, bool):        print(value, "is a boolean")    else:        print(value, "is not a boolean")
Output
True is a boolean
1 is not a boolean

Line by line

Line 2

True == 1 is True, but 1 is still an int, so the type check distinguishes them.

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