Online Learning Platform
In this python numpy program, we will test a given array element-wise is finite or not using NumPy.
import numpy as np
x = np.array([6,8,3,np.inf])
print(np.isfinite(x))
Output :
[ True True True False]
In this python numpy program, we will test whether none of the elements of a given array is zero using Numpy.
import numpy as np
x = np.array([6,0,1,0])
print(np.all(x))
Output :
False
In this python numpy program, we will test whether none of the elements of a given array is zero using Numpy.
import numpy as np
x = np.array([6,8,3,5])
print(np.all(x))
Output :
True
In this python numpy program, we will get the NumPy version installed in your IDE.
import numpy as np
print(np.__version__)
Output :
1.20.1
test whether none of the elements of a given array is zero.
Python program to convert a dictionary into n sized dictionary, In this dictionary program, will break the dictionary into a specified size and store it in a list.
1. Initiate three variables
N = 3 (size of the dictionary)
temp = {} (empty dictionary)
count = 1 (initiate counter)
output = [] (empty list to store output)2. Iterate through the dictionary data using the loop.
for val in Input_values3. Store key value in temp dictionary its size is equal to N, and
add temp to the output list, re-initiate after that count=1 . and temp={}
4. Print output.
input_dict = { 'a':1, 'b':2, 'c':3, 'd':4, 'e':5, 'f':6 }
N = 3
temp = {}
count = 1
output = []
for val in input_dict:
if count == N:
output.append(temp)
count = 1
temp = {}
else:
temp[val] = input_dict[val]
count+= 1
print("Output : ", output)
Output :
Output : [{'a': 1, 'b': 2}, {'d': 4, 'e': 5}]
Sort Dictionary by values summation
Python program to sort dictionary by value summation, In this dictionary program will sort the dictionary data as per the sum of list data in ascending order.
1. Create an empty dictionary temp, temp = {}
2. Iterate over the dictionary key and value with for loop.
for key, value in input_dict.items()
3. Add the key and sum of values in the temp dictionary.
temp[key] = sum(value)4. Sort all the elements of the dictionary using the sorted method.
which will return the list tuple of key and value pairs.
sorted(temp.items(), key=lambda x:x[1])
5. Convert a list of data into a dictionary.
output = dict(sorted_values)
6. print the output.
input_dict = { "x":[1,5,6], "y":[4,8,2], "c":[3,9] }
temp = {}
for key, value in input_dict.items():
temp[key] = sum(value)
sorted_values = sorted(temp.items(), key=lambda x:x[1])
output = dict(sorted_values)
print(output)
Output :
{ x:12, c:12, y:14}
In this python dictionary program, we will get the sum of unique elements from dictionary list values.
D1 = {'a':[6,7,2,8,1],'b':[2,3,1,6,8,10],'d':[1,8,2,6,9]}
l = []
for v in D1.values():
for num in v:
if num not in l:
l.append(num)
print("Sum: ",sum(l))
Output :
Sum: 46
reverse each string value in the dictionary and add an underscore before and after the Keys.
In this python dictionary program, we will reverse string value in the dictionary and add an underscore before and after the Keys.
D1 = {'a':'Python','b':'Programming','c':'Learning'}
D2 = {}
for k,v in D1.items():
D2['_'+k+'_'] = v[::-1]
print(D2)
Output :
{'_a_': 'nohtyP', '_b_': 'gnimmargorP', '_c_': 'gninraeL'}
sum unique elements from dictionary list values.
In this python dictionary program, we will invert a dictionary with non-unique hashable values.
from collections import defaultdict
D1 = {'alex':1,'bob':2,'martin':1,'robert':2}
obj = defaultdict(list)
for key, value in D1.items():
obj[value].append(key)
print(obj)
Output :
defaultdict(<class 'list'>, {1: ['alex', 'martin'], 2: ['bob', 'robert']})
In this python dictionary program, we will rename key of a dictionary
D1 = {'a':19,'b': 20,'c':21,'d':20}
D1['e'] = D1.pop('d')
print(D1)
Output :
{'a': 19, 'b': 20, 'c': 21, 'e': 20}