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Python practice problems help beginners to become experts in a python programming language with a small amount of practice effort.
In this program, we will print all odd numbers between 1 to 100.
for i in range(1,101):
if i%2 != 0:
print(i,end=" ")
Output :
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47
49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91
93 95 97 99
In this program, we will print all even numbers between 1 to 100.
for i in range(1,101):
if i%2 == 0:
print(i,end=" ")
Output :
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42
44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82
84 86 88 90 92 94 96 98 100
In this program, we will print all alphabets from a-z using a for loop.
import string
print("Alphabet from a-z:")
for letter in string.ascii_lowercase:
print(letter, end =" ")
print("\nAlphabet from A-Z:")
for letter in string.ascii_uppercase:
print(letter, end =" ")
Alphabet from a-z:
a b c d e f g h i j k l m n o p q r s t u v w x y z
Alphabet from A-Z:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
# small letter ascii range from 97-122
print("Alphabet from a-z")
for i in range(26):
# increase small letter ascii value by 1
# and print character with ascii value
print(chr(97 + i), end=' ')
# capital letter ascii range from 65-90
print("\nAlphabet from A-Z")
for i in range(26):
# increase capital letter ascii value by 1
# and print character with ascii value
print(chr(65 + i), end=' ')
Alphabet from a-z:
a b c d e f g h i j k l m n o p q r s t u v w x y z
Alphabet from A-Z:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
In this program, we will print all natural numbers in reverse (from n to 1) using a while loop
n = int(input("Enter the last number: "))
count = n
while count != 0:
print(count,end=" ")
count -= 1
Output :
Enter the last number: 10
10 9 8 7 6 5 4 3 2 1
In this program, we will print all natural numbers from 1 to n using a while loop.
n = int(input("Enter the last number: "))
count = 1
while count <= n:
print(count,end=" ")
count += 1
Output :
Enter the last number: 10
1 2 3 4 5 6 7 8 9 10
In this python program, we will print the alphabet pattern ‘O’, with a special character *. pattern printing programs are very helpful to get expertise on loop fundamentals and flow design.
Please refer to the image, we consider a square of 7×7 size, which means 7 rows and 7 colons, Now in this square, the circle marked as green will be part of the ‘0’ pattern.
1). In this program have considered the matrix of 7*7 and where each row colon’s initial index position is zero as shown in the image.
2). In the code first loop act and the row and nested loop act as colons to print the pattern.
3). First loop value range is 0-6 and the nested loop range is the same 0-6.
4). First If condition makes sure only three * will print in the first and last row.
5). Second if the condition makes sure only two * should print at 1 and 5 indexes of the colon, for remaining 5 rows.
for row in range(0, 7):
for column in range(0, 7):
# here in first and last row we want to three *
if (row == 0 or row == 6) and (1 < column < 5) :
print("*", end=' ')
# here from 2 to 6 row, * will print on 1 and 5 index only.
elif (0 < row <= 5) and (column ==1 or column ==5):
print("*", end=' ')
else:
print(" ", end=' ')
print()
Output :
---------
***
* *
* *
* *
* *
* *
***
---------
In this program, we will accept a string and calculate the number of digits and letters.
word = "python1234"
digit = 0
character = 0
for ele in word:
if ele.isalpha():
character += 1
elif ele.isnumeric():
digit += 1
print("Digits :",digit)
print("Characters: ",character)
Digits : 4
Characters: 6
inputstr = 'pythons12345'
digits = '0123456789'
letters = ''
# create small case and capital case sequence with ASCII
for i in range(1, 27):
letters = letters + chr(65+i) + chr(97+i)
digit_count = 0
letter_count = 0
# iterate over each character with loop
for word in inputstr:
# check if word is digit and increase digit count
if word in digits:
digit_count += 1
# check if word is letters and increase letter count
elif word in letters:
letter_count += 1
print("Digit Count :", digit_count)
print("Letter Count :", letter_count)
Digits Count : 5
Letter Count : 7
In this program, we will take a word as input from the user and convert all uppercase to lowercase in a word.
input1 = input("Enter word: ")
result = ''
for char in input1:
if char.isupper():
print(char.lower(),end="")
else:
print(char,end="")
Enter word: SQATOOLS
sqatools
str1 = input("Enter input string:")
result = ""
for char in str1:
# get character ascii value
char_ascii = ord(char)
# check ascii value between 65 - 90 range
# then character is in upper case
if 65 <= char_ascii <= 90:
# get character exact location
char_position = char_ascii - 65
# convert upper char ascii to lower case.
# add character to the result
result = result + chr(97+char_position)
else:
result = result + char
print("Result :", result)
Enter Input String: SQATOOLS Learning
Result : sqatools learning
In this program, we will print Fizz Buzz and FizzBuzz for multiples of certain numbers.
#Printing output
for i in range(1,31):
if i%3 == 0 and i%5 == 0:
print("FizzBuzz")
elif i%3 == 0:
print("Fizz")
elif i%5 == 0:
print("Buzz")
Output :
Fizz
Buzz
Fizz
Fizz
Buzz
Fizz
FizzBuzz
Fizz
Buzz
Fizz
Fizz
Buzz
Fizz
FizzBuzz
In this program, we will get the Fibonacci series between 0 to 20.
num1 = 0
num2 = 1
count = 0
while count < 20:
print(num1,end=" ")
n2 = num1 + num2
num1 = num2
num2 = n2
count += 1
Output :
0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181